![]() ![]() ![]() ![]() $$ W= 62.4 \int_$$ītw, the correct lb to kg conversion is 2.2 lb/kg and kg to ton(US) 907 kg/ton(US). $$ dW= 62.4 \times y \times \pi x^2 dy \times y$$Īnd since we are raising the water from the point $y = -2$ to $y = 0$ to make it appear that the water reaches the top of tank: Substituting this newly-found $dF$ to $dW$ described in the figure above: Find the fluid force of a square vertical plate submerged in water, where a 6, and the weight density of water is 9800 newtons per cubic meter. The force $F$ is equal to specific volume of liquid $\times$ distance $\times$ area or in differential form: $$dF = w \times h \times dA$$Īs seen in the figure above: $$dF = 62.4 \times y \times \pi x^2 dy$$ I'm getting the differential work $dW$: $$dW = dF \times x$$ $ The work done by a variable force from $x= a$ to $x = b$ is: $$W = \int_a ^b F(x) dx$$ (The weight-density of water is 62.4 pounds per cubic foot. I do know that $Work = Force \times distance. MY NOTES ASK YOUR TEACHER Find the fluid force on the vertical side of the tank, where the dimensions are given in feet. Find the work done in pumping the water to the top of the tank. I was studying for some exams when I encountered this question:Ī hemispherical tank of radius 6 feet is filled with water to a depth of 4 feet. ![]()
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